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mdct: work on 2 input buffers, and remove 1 encoding buffer

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This commit is contained in:
Antoine SOULIER
2022-05-05 13:54:50 +02:00
parent 0cec73a6fb
commit 3568ee1cbf
8 changed files with 63 additions and 63 deletions
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18
test/mdct.py
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@@ -99,11 +99,15 @@ def check_forward_unit(rng, dt, sr):
x = (2 * rng.random(ns)) - 1
mdct = MdctForward(dt, sr)
y = [ mdct.run(x), mdct.run(x) ]
y = [ None ] * 2
y_c = [ None ] * 2
y_c = [ lc3.mdct_forward(dt, sr, np.append(np.zeros(nd), x)),
lc3.mdct_forward(dt, sr, np.append(x[-nd:], x)) ]
mdct = MdctForward(dt, sr)
y[0] = mdct.run(x)
y[1] = mdct.run(x)
(y_c[0], d_c) = lc3.mdct_forward(dt, sr, x, np.zeros(nd))
y_c[1] = lc3.mdct_forward(dt, sr, x, d_c)[0]
ok = ok and np.amax(np.abs(y[0] - y_c[0])) < 1e-5
ok = ok and np.amax(np.abs(y[1] - y_c[1])) < 1e-5
@@ -118,12 +122,10 @@ def check_forward_appendix_c(dt):
nd = T.ND[dt][sr]
ok = True
y = lc3.mdct_forward(dt, sr,
np.append(np.zeros(nd), C.X_PCM[dt][0]))
(y, d) = lc3.mdct_forward(dt, sr, C.X_PCM[dt][0], np.zeros(nd))
ok = ok and np.amax(np.abs(y - C.X[dt][0])) < 1e-1
y = lc3.mdct_forward(dt, sr,
np.append(C.X_PCM[dt][0][-nd:], C.X_PCM[dt][1]))
(y, d) = lc3.mdct_forward(dt, sr, C.X_PCM[dt][1], d)
ok = ok and np.amax(np.abs(y - C.X[dt][1])) < 1e-1
return ok