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jtag: make caller always allocate buffer

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simplifies the API and there is only one remaining user at this point.

Is the implementation busted where the check does not actually happen
now?

Change-Id: I776a43766f5576a08df320f6fe41a2750d101bde
Signed-off-by: Øyvind Harboe <oyvind.harboe@zylin.com>
Reviewed-on: http://openocd.zylin.com/264
Tested-by: jenkins
Reviewed-by: Spencer Oliver <spen@spen-soft.co.uk>
This commit is contained in:
Øyvind Harboe
2011-12-13 23:44:34 +01:00
committed by Spencer Oliver
parent cb90d32e38
commit a30a4f0fc7
3 changed files with 2 additions and 41 deletions
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18
src/jtag/minidriver/minidriver_imp.h
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@@ -23,24 +23,6 @@
#include <jtag/jtag_minidriver.h>
static inline void interface_jtag_alloc_in_value32(struct scan_field *field)
{
field->in_value = field->intmp;
}
static inline void interface_jtag_add_scan_check_alloc(struct scan_field *field)
{
/* We're executing this synchronously, so try to use local storage. */
if (field->num_bits > 32)
{
unsigned num_bytes = DIV_ROUND_UP(field->num_bits, 8);
field->in_value = (uint8_t *)malloc(num_bytes);
field->allocated = 1;
}
else
field->in_value = field->intmp;
}
static inline void jtag_add_dr_out(struct jtag_tap* tap,
int num_fields, const int* num_bits, const uint32_t* value,
tap_state_t end_state)